Beam Calculator — Shear, Moment & Deflection Diagrams

Interactive Beam Calculator

Calculate shear, moment, and deflection diagrams for common beam configurations.

Beam Calculator

Shear, moment & deflection diagrams for common beam configurations

inftmmm

Steel — all grades (29,000 ksi)
Aluminum — all alloys (10,000 ksi)
Titanium (16,500 ksi)
Wood — Southern Pine (1,700 ksi)
Wood — Doug Fir (1,600 ksi)
Wood — SPF / Hem-Fir (1,200 ksi)
Wood — Red Oak (1,800 ksi)
Wood — White Oak (1,580 ksi)
Wood — Hard Maple (1,740 ksi)
Wood — Walnut (1,460 ksi)
Wood — Cherry (1,220 ksi)
Wood — Ash (1,340 ksi)
Concrete — f’c 4,000 psi (3,600 ksi)
Concrete — f’c 3,000 psi (3,122 ksi)
Concrete — f’c 5,000 psi (4,031 ksi)
Concrete — f’c 6,000 psi (4,415 ksi)
Concrete — f’c 8,000 psi (5,098 ksi)
Glulam — 24F-V4 (1,800 ksi)
LVL — 1.9E (1,900 ksi)
LVL — 2.0E (2,000 ksi)
Custom…

ksi

— Select shape or enter custom —
▭ Rectangle (enter b × h)

W6×10 (3.56 in⁴)
W8×24 (30.8 in⁴)
W8×31 (53.8 in⁴)
W10×33 (98.0 in⁴)
W10×49 (170 in⁴)
W12×40 (199 in⁴)
W12×50 (285 in⁴)
W12×58 (350 in⁴)
W14×48 (394 in⁴)
W14×61 (541 in⁴)
W16×67 (843 in⁴)
W18×76 (1,170 in⁴)
W21×93 (1,830 in⁴)
W24×104 (3,100 in⁴)

HSS 4×4×1/4 (6.36 in⁴)
HSS 6×6×1/4 (24.6 in⁴)
HSS 8×8×3/8 (64.2 in⁴)

Pipe 4 Std (7.23 in⁴)
Pipe 6 Std (28.1 in⁴)
Pipe 8 Std (72.5 in⁴)

2×4 (5.36 in⁴)
2×6 (20.80 in⁴)
2×8 (47.63 in⁴)
2×10 (98.93 in⁴)
2×12 (178.0 in⁴)
4×6 (30.66 in⁴)
4×8 (70.31 in⁴)
6×8 (111.1 in⁴)
6×10 (167.1 in⁴)
6×12 (697.1 in⁴)

2×4 (5.36 in⁴)
2×6 (20.80 in⁴)
2×8 (47.63 in⁴)
2×10 (98.93 in⁴)
2×12 (178.0 in⁴)

Custom…

in⁴

Rectangle Dimensions

×

in

I = bh³/12. Common: 2×12 = 1.5×11.25, 4×6 = 3.5×5.5, 6×8 = 5.5×7.5



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How It Works

Structural beam analysis determines internal forces, bending moments, and deflections that develop when loads are applied to horizontal structural members. These calculations form the foundation of safe structural design by ensuring beams can support applied loads without failure or excessive deflection.

Shear Force (V) represents the internal force tending to cut through the beam cross-section. For a simply supported beam with point load P at distance ‘a’ from the left support and distance ‘b’ from the right support:

  • Left reaction: R_A = P × b / L
  • Right reaction: R_B = P × a / L
  • Shear force: Changes abruptly at load application points

Bending Moment (M) represents the internal moment that causes beam curvature. Maximum moment typically occurs where shear force equals zero:

  • Simply supported beam, center load: M_max = P × L / 4
  • Cantilever beam, end load: M_max = P × L
  • Uniformly distributed load: M_max = w × L² / 8 (simply supported)

Deflection (δ) quantifies beam bending under load. Deflection formulas depend on loading pattern and support conditions:

  • Simply supported, center load: δ_max = P × L³ / (48 × E × I)
  • Cantilever, end load: δ_max = P × L³ / (3 × E × I)
  • Simply supported, uniform load: δ_max = 5 × w × L⁴ / (384 × E × I)

Where E represents the material’s modulus of elasticity and I represents the beam’s moment of inertia about its neutral axis. The moment of inertia depends on cross-sectional geometry and governs resistance to bending.

Beam theory assumes linear elastic behavior, plane sections remain plane after bending, and deflections remain small compared to beam dimensions. These assumptions apply to most structural engineering applications but may not suit highly flexible or nonlinear material behavior.

Practical Applications

Building Floor Systems: Residential and commercial floor joists must support occupancy loads plus the structure’s self-weight. A 2×10 Douglas fir joist spanning 4.8m (16 ft) with 1.9 kN/m² (40 psf) loading experiences maximum moment of 5.5 kN⋅m and deflection of 13 mm. Building codes typically limit deflection to L/360 under live loads, requiring engineers to check both strength and serviceability criteria.

Bridge Design: Highway bridge girders carry vehicle loads transferred through the deck system. A steel I-beam supporting a 40-ton truck load distributed over 3m length must resist maximum moments exceeding 300 kN⋅m while maintaining deflections under strict limits to prevent ride quality degradation. Load distribution and dynamic amplification factors complicate simple beam analysis for actual bridge design.

Machine Frame Design: Manufacturing equipment frames experience loads from operational forces, vibration, and component weights. A machining center bed supporting a 2000 kg workpiece plus cutting forces requires rigid construction to maintain dimensional accuracy. Deflections exceeding 0.05 mm can affect machined part quality, demanding high-stiffness beam designs with optimized cross-sections.

Crane and Lifting Equipment: Overhead crane runways carry moving loads that create varying moment and shear distributions. A 10-ton bridge crane on a 20m runway span creates maximum runway beam moments of approximately 500 kN⋅m when positioned for worst-case loading. Fatigue considerations become critical due to repeated loading cycles throughout equipment lifetime.

Frequently Asked Questions

How do I choose between simply supported and cantilever beam configurations?

Simply supported beams require supports at both ends but typically experience lower moments and deflections than cantilevers of equal span. Cantilevers offer structural and architectural advantages when end supports are impractical, but require stronger construction due to higher root moments. Consider support feasibility, load patterns, deflection limits, and construction economy when selecting beam configurations.

What’s the difference between allowable stress design and ultimate strength design?

Allowable stress design (ASD) applies safety factors to material properties, ensuring calculated stresses stay below reduced allowable values. Ultimate strength design (USD or LRFD) applies separate factors to loads and material capacities, providing more rational safety treatment. Both approaches aim to prevent failure, but USD methods better account for load variability and material property uncertainty.

How do concentrated vs. distributed loads affect beam behavior?

Concentrated loads create localized high moments and sharp changes in shear force diagrams. Distributed loads produce smoother moment diagrams with more gradual variations. Real structures often experience combined loading patterns. Concentrated loads may require local reinforcement at application points, while distributed loads generally govern overall beam sizing.

When do I need to consider beam self-weight in calculations?

Include self-weight when it represents significant percentage of total load (typically >10%) or when deflection accuracy matters. Steel beams are dense but strong, so self-weight often matters less than applied loads. Concrete beams have lower strength-to-weight ratios, making self-weight more significant. Long spans and light applied loads make self-weight proportionally more important.

How do I handle beams with multiple loads or complex support conditions?

Superposition principle allows combining effects from multiple load cases when material behavior remains linear elastic. Calculate moments, shears, and deflections for each load separately, then add results algebraically. Complex support conditions (multiple supports, springs, rotational restraints) require more advanced analysis methods like finite element analysis or structural analysis software.